contestada

km
Two buses leave a station at the same time and travel in opposite directions. One bus travels 10 - - slower than the other. If the two buses are 1442
kilometers apart after 7 hours, what is the rate of each bus?
Rate of the slower bus:
X
5
?
Rate of the faster bus:​

Respuesta :

Answer:

The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph  .

Step-by-step explanation:

Given as :

The two buses apart 1442 km

The time taken for apart = 7 hours

Let The speed of faster bus = x kmph

The speed of slower bus = ( x - 10 ) kmph

Now Speed = [tex]\dfrac{\textrm distance}{\textrm time}[/tex]

∵ Both the buses traveling in opposite direction

So, The speed of faster bus + the speed of slower bus =  [tex]\dfrac{\textrm distance cover}{\textrm time}[/tex]

Or, x + x - 10 = [tex]\frac{1442}{7}[/tex]

or, 2 x = 206 + 10

or, 2 x = 216

∴  x = [tex]\frac{216}{2}[/tex]

I.e x = 108  kmph

So, The speed of faster bus = x = 108 kmph

And The speed of slower bus = ( x - 10 ) = 108 - 10 = 98 kmph

Hence The speed of faster bus is 108 kmph and The speed of slower bus is 98 kmph  . Answer

Otras preguntas