Answer:
The spacing is 5.15 μm.
Explanation:
Given that,
Electron with energy = 25 eV
Wave length = 0.25 nm
Separation d= 0.16 mm
Distance D=3.3 m
We need to calculate the spacing
Using formula of width
[tex]\beta=\dfrac{\lambda D}{d}[/tex]
Put the value into the formula
[tex]\beta=\dfrac{0.25\times10^{-9}\times3.3}{0.16\times10^{-3}}[/tex]
[tex]\beta=5.15\times10^{-6}\ m[/tex]
[tex]\beta=5.15\ \mu m[/tex]
Hence, The spacing is 5.15 μm.
