Answer: 2500km/s
Explanation:
use equation wich conects distance and acceleration:
S=Vst+at²/2
Vs=0km/s(from rest)
S=at²/2
S2=at²
t=√2S/a
t=√2*125km/25000 km/s²
t=0.1s
Vf --final velocity
Vs-- start velocity
a=Vf-Vs/t
at=Vf-Vs
Vs=0Km/s
at=Vf
25000Km/s*0.1s=Vf
Vf=2500Km/s