Answer:
[tex]2.557\times 10^{-2}\ molal.[/tex]
Explanation:
Given , molarity of glycerol= [tex]2.55\times 10^-^2\ M.[/tex]
Volume= 1 L.
Therefore, No of moles of glycerol= [tex]molarity\times volume\ in\ liters=2.55\times 10^-^2\ moles.[/tex]
Now, volume of water needed, V=998.8 mL.
Density is given as= 0.9982 g/mL.
Therefore, mass of water = [tex]volume\times density=998.8\times 0.9982=997\ g=0.997\ kg[/tex]
Now, molality=[tex]\dfrac{no\ of\ moles}{mass\ of\ solvent\ in\ kg}=\dfrac{2.55\times 10^-^2\ }{0.997}=0.02557\ molal=2.557\times 10^{-2}\ molal.[/tex]
Hence, this is the required solution.
