The demand for subassembly S is 8080 units in week 7. Each unit of S requires 11 unitnothing of T and 11 unitnothing of U. Each unit of T requires 22 unitss of V, 22 unitss of W, and 22 unitss of X. Finally, each unit of U requires 11 unitnothing of Y and 33 units of Z. One firm manufactures all items. It takes 2 weeks to make S, 22 weekss to make T, 2 weeks to make U, 22 weekss to make V, 22 weeks to make W, 11 weeknothing to make X, 2 weeks to make Y, and 22 weekss to make Z. Suppose that in addition to 8080 units of S, there is also a demand for 3030 units of U, which is a component of S. The 3030 units of U are needed for maintenance purposes. These units are needed in week 6. Additionally, a new order has been received for 9090 units of S due in week 8. Modify the net material requirements plan to reflect these changes.

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cancinodavidq cancinodavidq · Answer 1 · 2019-12-21T14:08:39+01:00

Answer:

Please find the detailed answer as follows:

Explanation:

Consider the table attached in the excel.

The above are the requirements of the units of material if demand of 8080 units of S has to be completed.

The requirement of units of U for maintenance is given in the second table.

As the lead time for S is two weeks the components should be ready by the fifth week.

As the lead time for components T and U both is 2 weeks their components should be ready by the third week.

Hence in the first week the required number of units of V, W, Y and Z are to be ordered as all of them are required in the third week.

The required number of units of X are to be ordered in the second week to be ready in third week.

The required units of U, Y and Z are to be ordered considering the requirement to make S plus the maintenance requirements.