The area and perimeter of geometry are 32.18 cm. sq and 23.9137 cm respectively
Mensuration
It is the branch of geometry that deals with the measurement of length, area, surface area, volume, etc.
Given
AB = 6cm
BC = 6cm
How to calculate the area and the perimeter?
Base = 6
Height = 6
Radius(r) = 3
According to Pythagoras theorem
[tex]AC^{2} =AB^{2} +BC^{2} \\AC^{2} =6^{2} +6^{2} \\AC= 6\sqrt{2} \\AC = 8.4852[/tex]
Then the area of geometry will be
[tex]\rm Area\ of\ geometry\ =\ Area\ of\ triangle\ +\ Area\ of\ semi\ circle\\Area\ of\ geometry\ = \dfrac{1}{2} *\ base\ *\ height\ +\ \pi\ \dfrac{r^{2} }{2} \\Area\ of\ geometry\ =\ \frac{1}{2}\ 6*\ 6\ +\ \pi \dfrac{3^{2} }{2} \\Area\ of\ geometry\ =\ 18\ +\ 14.13\\Area\ of\ geometry\ =\ 32.18\ cm^{2}[/tex]
Then perimeter of the geometry
[tex]\rm perimeter\ of\ the\ geometry =\ AB+AC+ perimeter\ of\ semicircle\\perimeter\ of\ the\ geometry =\ AB+AC+ \pi r\\perimeter\ of\ the\ geometry =\ 6+8.4852+3\pi \\perimeter\ of\ the\ geometry =\ 23.9137\ cm[/tex]
Thus, the area and perimeter of geometry are 32.18 cm. sq and 23.9137 cm respectively.
More about the mensuration link is given below.
https://brainly.com/question/1447350
