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Drag numbers to complete a function in terms of x and y for the line that contains the points (2, 4) and (6, 16). Numbers may be used once, more than once, or not at all.

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luisejr77

Answer: [tex]y=3x-2[/tex]

Step-by-step explanation:

Since there is not image attached, below is the explanation to find the equation of the line that contains the points (2, 4) and (6, 16), in Slope-Intercept form:

The Slope-Intercept form of the equation of the line is:

[tex]y=mx+b[/tex]

Where "m" is the slope and "b" is the y-intercept.

You can find the slope of the line with this formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Now, given the points (2, 4) and (6, 16), you can say that:

[tex]y_2=16\\y_1=4\\\\x_2=6\\x_1=2[/tex]

So, substituting values, you get:

[tex]m=\frac{16-4}{6-2}=3[/tex]

Now you can ubstitute the slope and the coordinates of one of the given points into [tex]y=mx+b[/tex] and solve for "b":

[tex]4=3(2)+b\\\\4-6=b\\\\b=-2[/tex]

Therefore, you can determine that the equation of this line is:

[tex]y=3x-2[/tex]

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