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A bag contains 10 blue, 6 green, and 4 red marbles. You choose a marble with one hand and then a second marble with the other hand. What is the probability that you will first choose a red marble followed by a green marble? CLEAR CHECK P(red then green) = 695 6 9 5 P(red then green) = 12 1 2 P(red then green) = 350 3 5 0 P(red then green) = 19

Respuesta :

Answer:

6/95.

Step-by-step explanation:

Prob(red marble on the first choice) =  4/(10+6+4)

= 4/20

= 1/5.

Prob(green marble on the second draw) = 6/19.

Prob( read then a green)

= 1/5 * 6/19

= 6/95.

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