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luisejr77

Answer:  3) Sydney arrives 1 hour before Nathan.

Step-by-step explanation:

The complete exercise is:

Nathan and Sydney start out together on a bike trail that is 24 miles long. Nathan bikes at 8 miles per hour. Sydney bikes at 12 miles per hour. Which statement is true?

1) Nathan arrives 1 hour later than Sydney.

2) Nathan arrives 4 hours later than Sydney.

3) Sydney arrives 1 hour before Nathan.

4) They arrive at the same time.

You need to remember that:

[tex]V=\frac{d}{t}[/tex]

Where "V" is the speed, "d" is distance and "t" is time.

If you solve for "t", this is:

[tex]t=\frac{d}{V}[/tex]

Calculate the time it takes to Nathan arrives to the end of the bike trail.

Knowing that:

[tex]d_1=24\ mi\\\\V_1=8 \frac{mi}{h}[/tex]

Therefore, you get:

[tex]t_1=\frac{24\ mi}{8 \frac{mi}{h}}\\\\t_1=3\ h[/tex]

Calculate the time it takes to Sidney arrives to the end of the bike trail.

Knowing that:

[tex]d_2=24\ mi\\\\V_2=12 \frac{mi}{h}[/tex]

Then,you get:

[tex]t_2=\frac{24\ mi}{12 \frac{mi}{h}}\\\\t_2=2\ h[/tex]

You can notice that Sidney arrives first.

So, subtracting the times calculated, you get:

[tex]t_1-t_2=3\ h-2\ h=1\ h[/tex]

Based on this, you can conclude that Sydney arrives 1 hour before Nathan.