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Which equation has the same solutions as the equation given below?

x^2 +18x+32=0

A. (x+4)^2=81

B. (x+9)^2=49

C. (x+6)^2=36

D. (x+2)^2=16

Respuesta :

bayaankoolinaasir

Answer:

B

Step-by-step explanation:

Also solved eveything

(x+9)^2=49

x^2+18x+81=49

x^2+18x+32=0

a=1, b=18 and c=32

x= (-18 +/- Sqrt (18^2-4×32))/2

x= (-18 +/- Sqrt (324-128))/2

x= (-18 +/- Sqrt (196))/2

x= (-18 +/- 14)/2

x= (-18 +14)/2 = -4/2 =-2

OR

x= (-18 -14)/2 = -32/2 =-16

BasketballEinstein

Answer:

B. [tex]\displaystyle (x + 9)^2 = 49[/tex]

Step-by-step explanation:

For Quadratic Equations, [tex]\displaystyle y = Ax^2 + Bx + C,[/tex] use the formula [tex]\displaystyle [\frac{b}{2}]^2[/tex] to complete the square:

[tex]\displaystyle (x^2 + 18x + 81) + k \\ (x^2 + 18x + 81) - 49 \\ \\ (x + 9)^2 - 49 → (x + 9)^2 = 49[/tex]

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