5.4 moles of CO2 will be produced from 79.0 g of C3H8 assuming O2 is available in excess.
According to this question, the balanced equation of the given reaction is as follows:
C3H8 + 5O2 → 3CO2 + 4H2O
1 mole of propane produces 3 moles of CO2.
moles of C3H8 = 79g ÷ 44g/mol
moles of C3H8 = 1.80mol
This means that 1.8 moles of propane 1.8 × 3 = 5.4 moles
Therefore, 5.4 moles of CO2 will be produced from 79.0 g of C3H8 assuming O2 is available in excess.
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