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a solution is made by dessolving 609 of NAOH (M = 40g*mol^-1) in enough distilled water to make 300ml of stock solution. what is the volumes of this solution and the distilled water when mixed will result in a soluteion that is approximately 1 M NAOH?

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Answer:

For example, 20mL of stock solution with 80mL of water.

Explanation:

60g of NaOH in 0,300L have a molar concentration of:

60g NaOH × ( 1 mol / 40g) = 1,5 moles of NaOH / 0,300L = 5M

If you want to mix this solution with water to produce a 1M NaOH solution you need to mix 1 part of volume of the stock solution per 5 parts of total volume. For example, mix 20mL of stock solution with 80mL of water. That is:

5M NaOH × ( 20mL stock solution / 20mL + 80mL -Total volume-) = 1M NaOH solution

I hope it helps!

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