Answer:
change in temperature of iron cube is 233 degree
Explanation:
given data
length = 5 cm
volume increase dV = 0.35 cm³
coefficient linear expansion α = 1.2 × [tex]10^{-5}[/tex]
to find out
change in temperature of iron cube
solution
we get here first initial volume that is
initial volume = 5³
initial volume = 125 cm ³
and we consider here change in temperature is dT
so volume increase will be here as
dV = V × α × dT ......................1
0.35 = 125 × 1.2 × [tex]10^{-5}[/tex] × dT
solve we get
dT = 233 degree
so change in temperature of iron cube is 233 degree