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This molecule can be synthesized from an alkyne anion and an alkyl bromide. However, there are two ways in which this molecule can be formed. One way uses a higher molecular weight alkyne anion (Part 1) and the other uses a lower molecular weight anion (Part 2). Draw the two versions in the boxes below. Omit spectator ions.

Respuesta :

Answer:

See figures

Explanation:

In this case, we will have different options around the triple bond. On part 1 we have to use the bigger anion, so we have to use the anion in which the benzene ring is included therefore the ethyl would be the halide (see figure 1).

On part 2 we have to use the smaller anion, so the ethyl group would be the anion and the other part of the molecule would be the alkyl halide (see figure 2).

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