Answer:
0.47 is the probability it rains at least 2 out of any randomly selected 5 days during the given time of year
Step-by-step explanation:
We are given the following information:
We treat training as a success.
P(Rain) = 30% = 0.30
Then the chances of rain on each day follows a binomial distribution, where
[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 5
We have to evaluate:
[tex]P(x \geq 2) =1- P(x = 0) + P(x = 1) \\=1- \binom{5}{0}(0.3)^0(1-0.3)^5 - \binom{5}{1}(0.3)^1(1-0.3)^4\\=1- 0.16807- 0.36015\\= 0.47178 \approx 0.47[/tex]
0.47 is the probability it rains at least 2 out of any randomly selected 5 days during the given time of year