Suppose a geyser has a mean time between eruptions of 91 minutes91 minutes. If the interval of time between the eruptions is normally distributed with standard deviation 28 minutes28 minutes​, answer the following questions. ​(a) What is the probability that a randomly selected time interval between eruptions is longer than 103103 ​minutes?

Respuesta :

Answer:

0.3341  is the probability that a randomly selected time interval between eruptions is longer than 103 ​minutes.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 91 minutes

Standard Deviation, σ = 28 minutes

We are given that the distribution of  time between the eruptions is a bell shaped distribution that is a normal distribution.

Formula:

[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]

a) P( time interval between eruptions is longer than 103 ​minutes)

P(x > 103)

[tex]P( x > 103) = P( z > \displaystyle\frac{103 - 91}{28}) = P(z > 0.4286)[/tex]

[tex]= 1 - P(z \leq 0.4286)[/tex]

Calculation the value from standard normal z table, we have,  

[tex]P(x >103) = 1 - 0.6659 = 0.3341 = 33.41\%[/tex]

0.3341  is the probability that a randomly selected time interval between eruptions is longer than 103 ​minutes.