Answer:
B. 161.5 J
Explanation:
[tex]n[/tex] = Number of moles = 0.37
[tex]\Delta T[/tex] = Rise in the temperature of the oxygen gas = 15 K
[tex]Q[/tex] = heat added in order to raise the temperature
[tex]c_{p}[/tex] = specific heat at constant pressure = 3.5
At constant pressure, heat is given as
[tex]Q = n c_{p} R \Delta T\\Q = (3.5) (0.37) (8.314) (15)\\Q = 161.5 J[/tex]