Answer:
1176 N
Explanation:
We are given that
Mass of car=[tex]m_1=[/tex]1280 kg
Mass of trailer=[tex]m_2[/tex]=350 kg
Car exerts a horizontal force against the ground =[tex]3.6\times 10^{3}[/tex]N
Coefficient of friction=[tex]\mu=0.15[/tex]
We have to find the force exerted by car on the trailer.
[tex]F=(m_1+m_2)a+F_f[/tex]
[tex]F=(m_1+m_2)a+\mu m_2g[/tex]
[tex]g=9.8 m/s^2[/tex]
Substitute the values then we get
[tex]3.6\times 10^{3}=(1280+350)a+0.15\times 350\times 9.8[/tex]
[tex]3.6\times 10^{3}=1630a+514.5[/tex]
[tex]1630a=3600-514.5=3085.5[/tex]
[tex]a=\frac{3085.5}{1630}=1.89 m/s^2[/tex]
Force exert on the trailer
[tex]F=m_2a+\mu m_2g[/tex]
[tex]F=350(1.89)+0.15\times 350\times 9.8[/tex]
[tex]F=1176 N[/tex]
Hence, the car exerts force on the trailer=1176 N
