Answer:
Explanation:
Given
diameter [tex]d=20 \mu m[/tex]
density [tex]\rho =1300 kg/m^3[/tex]
frequency [tex]\nu =150 Hz[/tex]
Length of silk strand [tex]L=14 cm[/tex]
Velocity in the string is as follows
[tex]\nu =\sqrt{\frac{T}{\mu }}[/tex]
The expression for Fundamental Frequency
[tex]f=\frac{\nu }{2l}[/tex]
[tex]f=\frac{1}{2l}\times \sqrt{\frac{T}{\mu }}[/tex]
[tex]f=\frac{1}{2l}\times \sqrt{\frac{T}{\frac{m}{l}}}[/tex]
[tex]f=\frac{1}{2l}\times \sqrt{\frac{Tl}{\rho V}}[/tex]
Squaring
[tex]f^2=\frac{1}{4l^2}\times \frac{Tl}{\rho V}[/tex]
[tex]T=4\rho \cdot A\cdot l^2\cdot f^2[/tex]
[tex]T=4\times 1300\times \frac{\pi }{4}(20\times 10^{-6})^2\times (0.14)^2\times 150^2[/tex]
[tex]T=7.2\times 10^{-4} N[/tex]
