Answer:
[tex]1.7\cdot 10^{15} g[/tex]
Explanation:
Glucose reacts with oxygen do produce carbon dioxide and water:
[tex]C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)[/tex]
Given a daily mass of glucose:
[tex]m_1 = 5.0\cdot 10^2 g[/tex]
Find moles of glucose:
[tex]n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol[/tex]
From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:
[tex]n_2 = 2.775 mol\cdot 6=16.65 mol[/tex]
Convert this into mass using the molar mass of carbon dioxide:
[tex]m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g[/tex]
This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:
[tex]732.8 \frac{g}{person\cdot day}\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^{15} g[/tex]
