Answer:
60.795 J
60.795 J
Explanation:
P = Pressure = 3 atm
[tex]dU[/tex] = Internal energy = [tex]nC_vdT=0[/tex]
[tex]V_f[/tex] = Final volume = 600 mL
[tex]V_i[/tex] = Initial volume = 400 mL
Work done is given by
[tex]dW=PdV\\\Rightarrow dW=P(V_f-V_i)\\\Rightarrow dW=3\times 101325\times (600-400)\times 10^{-6}\\\Rightarrow dW=60.795\ J[/tex]
The total work done by the gas in the process is 60.795 J
Total heat flow is given by
[tex]dQ=dU+dW\\\Rightarrow dQ=nC_vdT+dW\\\Rightarrow dQ=0+60.795 J\\\Rightarrow dQ=60.795\ J[/tex]
The total heat flow into the gas is 60.795 J
a. The total work done by the gas in the process is 60.795J
b. The total heat flow into the gas is 60.795 J.
Since
P = Pressure = 3 atm
dU= Internal energy = 0
Vf = Final volume = 600 mL
Vi = Initial volume = 400 mL
a.
The work done is
= PdV
= P(vf - vi)
= 3*101325*(600-400)*10^-6
= 60.795J
b. Now the total heat flow is
= 0 + 60.795J
= 60.795J
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