Answer:
The magnitude of centripetal force is 130 N.
Explanation:
It is given that,
Mass, m = 60 kg
Diameter of the merry go round, d = 4 m
Radius, r = 2 m
Time for rotation, t = 6 s
We know that we will feel some of the outward force and this force is known as centripetal force. Its formula is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
v is the velocity
[tex]v=\dfrac{2\pi r}{t}[/tex]
[tex]v=\dfrac{2\pi \times 2}{6}[/tex]
v = 2.09 m/s
[tex]F=\dfrac{60\times (2.09)^2}{2}[/tex]
F = 131.04 N
or
F = 130 N
So, the magnitude of centripetal force is 130 N. Hence, this is the required solution.
