Answer:
a = 162.7 m/s²
Explanation:
given,
radius = 1.5 m
height above ground level = 2 m
horizontal distance = 10 m
magnitude of centripetal acceleration = ?
we know,
centripetal acceleration
a =[tex]\dfrac{v^2}{r}[/tex]
using equation of motion
[tex]s = u t + \dfrac{1}{2}at^2[/tex]
[tex]s =\dfrac{1}{2}gt^2[/tex]
[tex] t = \sqrt{\dfrac{2s}{g}}[/tex]
[tex] t = \sqrt{\dfrac{2\times 2}{9.8}}[/tex]
t = 0.64 s
velocity
[tex]v = \dfrac{s}{t}[/tex]
[tex]v = \dfrac{10}{0.64}[/tex]
v = 15.625 m/s
centripetal acceleration
a =[tex]\dfrac{15.625^2}{1.5}[/tex]
a = 162.7 m/s²
