Answer:
1.40625 kg-m^2
Explanation:
Supposing we have to calculate rotational moment of inertia
Given:
Mass of the ball m= 2.50 kg
Length of the rod, L= 0.78 m
The system rotates in a horizontal circle about the other end of the rod
The constant angular velocity of the system, ω= 5010 rev/min
The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less
[tex]I_{sys}= mL^2= 2.50\times 0.75^2[/tex]
=1.40625 kg-m^2
m= mass of the ball and L= length of the ball
