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A square 1300-turn coil with the area of 0.2 m2 is situated in the xy-plane in a region where the magnetic field is (50k) μT. What is the average induced emf when this coil is rotated into the xz-plane in 0.2 s?

Respuesta :

Answer:

e = 65 mA

Explanation:

given,

number of turn = 1300

Area = 0.2 m²

B = 50 x 10⁻⁶T

t = 0.2 s

coil rotate in x-z plane

θ = 90°  to θ = 0°

maximum induced emf

[tex]e = -\dfrac{BAn(cos \theta_f - cos\theta_i)}{\Delta t}[/tex]

[tex]e = -\dfrac{1300 \times 0.2 \times 50\times 10^{-6}(cos 90^0- cos0^0)}{0.2}[/tex]

e =0.065

e = 65 mA

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