A force of 45 N is applied tangentially to the rim of a solid disk of radius 0.12 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 140 rad/s2. Determine the mass of the disk.

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aristeus aristeus · Answer 1 · 2019-12-24T04:48:44+01:00

Answer:

Mass of the disk will be 2.976 kg

Explanation:

We have given force F = 45 N

Radius of the disk r = 0.12 m

Angular acceleration [tex]\alpha =140rad/sec^2[/tex]

We know that torque [tex]\tau =I\alpha[/tex]

And [tex]\tau =Fr[/tex]

So [tex]Fr=I\alpha[/tex] , here I is moment of inertia

So [tex]50\times 0.12=I\times 140[/tex]

[tex]I=0.0428kgm^2[/tex]

We know that moment of inertia [tex]I=\frac{1}{2}mr^2[/tex]

So [tex]0.0428=\frac{1}{2}\times m\times 0.12^2[/tex]

m = 2.976 kg