Respuesta :
Answer:
a) 12/25
b) 1/25
c) 12/25
Step-by-step explanation:
a) The first order can go anywhere, so it has 5 possibilities out of 5. The second order can go to any distributor except the one that got the first order, so it has 4 possibilities out of 5. The third order may go to any of the 3 remaining distributors, giving us 3 chances out of 5. So the probability is 5/5*4/5*3/5 = 12/25
b) The first order, again, can go anywhere, so it has 5 out of 5. The second and third order have to go to the same distributor, so, in each case, we have only 1 option available out of 5. The probability of this event is 5/5*1/5*1/5 = 1/25
c) This event is the complementary event of the union of the other 2 events the exercise has. If neither the same distributor got all 3 orders non all orders go to different distributors, then necessarily one distributor should got 2 orders and other 1. The probability of this event is, therefore 1-12/25-1/25 = 12/25.
The probabilities can be found to be:
- Probability (Different distributors) = 0.48.
- Probability ( Same distributor) = 0.04.
- Probability (Two of three to one distributor) = 0.16.
What is the probability that all orders go to different distributors?
This can be found as:
= Number of ways of going to all distributors / Number of ways 3 orders can be placed to 5 distributors
Solving gives:
= (5 x 4 x 3) / (5 x 5 x 5)
= 60 / 125
= 0.48
What is the probability that all orders go to different distributors?
If they all go to one distributor then the number of ways it can get to either distributor is 5 as there are 5 distributors:
= 5 / 125
= 1 / 25
= 0.04
What is the probability that two of the three orders go to one distributor?
As it is two orders going to one distributor, there is no chance of a third distributor getting an order. Probability will be:
= (5 x 4) / (5 x 5 x 5)
= 20 / 125
= 0.16
Find out more on probabilities at https://brainly.com/question/3642690.
