Respuesta :
Answer:
s=0.0500826
Step-by-step explanation:
adding 10 as their base
log14/3+log11/5-log22/15=log
swap the sides
10s= log14/3+log11/5-log22/15
divid both sides by 10
log10 14/30+log10 11/50-log10 22/150
s=0.0500826
Answer:
log(7)
Step-by-step explanation:
[tex]\log{\dfrac{14}{3}}+\log{\dfrac{11}{5}}-\log{\dfrac{22}{15}}=\log{\dfrac{\dfrac{14}{3}\cdot\dfrac{11}{5}}{\dfrac{22}{15}}}=\log{\dfrac{14\cdot 11}{22}}\\\\=\log{7}[/tex]
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The applicable rules of logarithms are ...
- log(ab) = log(a) +log(b)
- log(a/b) = log(a) -log(b)