contestada

A block is pulled along a horizontal surface at a constant speed by a force (14.1i 0 j 5.1k). The direction k is perpendicular to the surface. The block moves 6 m. How much work, in N m, does the force do?

Respuesta :

Answer:

[tex]W =84.6\ Nm[/tex]

Explanation:

given,

F = 14.1 i + 0 j + 5.1 k

displacement = 6 m

Assuming block is moving in x- direction

we know,

 dW = F dx

[tex]\int dW = F\int dx[/tex]

[tex]W = F\int_0^6 dx[/tex]

[tex]W = F[x]_0^6[/tex]

[tex]W = 14.1 \times 6[/tex]

[tex]W =84.6\ Nm[/tex]

hence, work done by the force is equal to [tex]W =84.6\ Nm[/tex]

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