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A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the magnitude of the cart’s displacement after the first 4.0 s of its motion?

Respuesta :

usmanbiu

Answer:

32 m

Explanation:

initial velocity (u) = 2 m/s

accceleration (a) = 3 m/s^{2}

time (t) = 4 s

What is the magnitude of the cart’s displacement (s) after the first 4.0 s of its motion?

from the equation of motion, displacement (s) = [tex]ut + 0.5at^{2}[/tex]

where

  • u is the initial velocity
  • t is the time
  • a is the acceleration

inserting all required values into  (s) = [tex]ut + 0.5at^{2}[/tex]          

(s) = [tex]2x4 + 0.5x3x4^{2}[/tex]

s = 8 + 24

s = 32 m

onyebuchinnaji

The magnitude of the cart's displacement is 32 m.

The given parameter:

initial velocity of the cart, u = 2 m/s

acceleration of the cart, a = 3 m/s²

time of motion of the car, t = 4 s

To find:

  • the magnitude of the cart’s displacement

The displacement of the cart is calculated by using second equation of motion:

[tex]s = ut + \frac{1}{2} at^2\\\\s = 2\times 4 \ + \ 0.5 \times 3 \times 4^2\\\\s = 8 \ + \ 24\\\\s = 32 \ m[/tex]

Thus, the displacement of the cart is 32 m.

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