Answer:
force acting on small piston is 200 N
Explanation:
given data
cross-sectional area a = 2.0 cm² = 2 × [tex]10^{-4}[/tex] m²
cross-sectional area a = 100 cm²= 100 × [tex]10^{-4}[/tex] =[tex]10^{-2}[/tex]m²
force f = 10,000 N
to find out
force acting on small piston
solution
we know that here pressure will be equal at all level in horizontal
so pressure at p1 = pressure p2
and pressure = [tex]\frac{force}{area}[/tex]
so [tex]\frac{force1}{area1}[/tex] = [tex]\frac{force2}{area2}[/tex]
put here value we get
[tex]\frac{force1}{2*10^{-4}}[/tex] = [tex]\frac{10000}{10^{-2}}[/tex]
solve it we get
force 1 = 200 N
so force acting on small piston is 200 N
