Answer:
20.6 K
Explanation:
The root mean square velocity is the square root of the average of the square of the velocity. It can be calculated using the following expression.
[tex]v_{rms}=\sqrt{\frac{3RT}{M} }[/tex]
where,
[tex]v_{rms}[/tex]: root mean square velocity
R: ideal gas constant
T: absolute temperature
M: molar mass
Then, we can find the temperature,
[tex]v_{rms}=\sqrt{\frac{3RT}{M} }\\T=\frac{v_{rms}^{2}M }{3R} =\frac{(505m/s)^{2}2.0159 \times 10^{-3} kg/mol}{3 \times (8.314 J/mol.K)} =20.6 K[/tex]
