a ultrasonic wave at 8x10^4 Hz is emitted into a vien where the speed of sound in blood is 1570 m/s. the wave reflects off the red blood cells moving towards the stationary receiver, if the frequency of the4 returning signal is 8.002x10^4 Hz, what is the speed of blood flow?

Respuesta :

Answer: 0.392 m/s

Explanation:

The Doppler shift equation is:

[tex]f'=\frac{V+V_{o}}{V-V_{s}} f[/tex]

Where:

[tex]f=8(10)^{4} Hz[/tex] is the actual frequency of the sound wave

[tex]f'=8.002(10)^{4} Hz[/tex] is the "observed" frequency

[tex]V=1570 m/s[/tex] is the speed of sound

[tex]V_{o}=0 m/s[/tex] is the velocity of the observer, which is stationary

[tex]V_{s}[/tex] is the velocity of the source, which are the red blood cells

Isolating [tex]V_{s}[/tex]:

[tex]V_{s}=\frac{V(f'-f)}{f'}[/tex]

[tex]V_{s}=\frac{1570 m/s(8.002(10)^{4} Hz-8(10)^{4} Hz)}{8.002(10)^{4} Hz}[/tex]

Finally:

[tex]V_{s}=0.392 m/s[/tex]