Answer:
[tex]3\frac{1}{2}\ units[/tex]
Step-by-step explanation:
we know that
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
[tex](-2\frac{1}{2},-3)\ and\ (1,-3)[/tex]
Convert mixed number to an improper fraction
[tex]2\frac{1}{2}=\frac{2*2+1}{2}=\frac{5}{2}[/tex]
so
we have
[tex](-\frac{5}{2},-3)\ and\ (1,-3)[/tex]
substitute the values in the formula
[tex]d=\sqrt{(-3+3)^{2}+(1+\frac{5}{2})^{2}}[/tex]
[tex]d=\sqrt{(0)^{2}+(\frac{7}{2})^{2}}[/tex]
[tex]d=\frac{7}{2}\ units[/tex]
Convert to mixed number
[tex]\frac{7}{2}\ units=\frac{6}{2}+\frac{1}{2}=3\frac{1}{2}\ units[/tex]
