The pressure exerted on the floor by each leg of the chair will be 1559.2 N/m². Pressure is defined as the force exerted on the unit area.
The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.
It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.
The given data in the problem is;
Person weight,(M)=79 kg
Chair weight,(m)=3.7 kg
Diameter(d)= 1.3 cm=1.3 ×10⁻² m
Pressure(P)=?
The total weight force by the chair on the surface is the sum of the weight of the chair and person weight;
The total weight is;
Total weight = 79 +3.7
Total weight = 82.7 kg
The total weight is divided into the four legs is;
[tex]\rm w= \frac{82.7 }{4} \\\\ w= 20.675\ kg[/tex]
The area of the contact of the chair to the surface is;
[tex]\rm A = \pi r^2 \\\\ A= 3.14 \times (0.65)^2 \\\\ A= 1.326 \ cm^2 \\\\ A=0.01326 \ m^2[/tex]
The pressure is found as;
[tex]\rm P =\frac{F}{A} \\\\ P= \frac{20.675}{0.01326 } \\\\\ P=1559.2 \ N/M^2[/tex]
Hence,the pressure exerted on the floor by each leg of the chair will be 1559.2 N/m²
To learn more about the pressure, refer to the link;
https://brainly.com/question/356585
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