Respuesta :
Answer:
A, B, C
Explanation:
Notice that this reaction involves double arrows, meaning this represents an equilibrium reaction in which we observe a forward reaction (combination of hemoglobin and oxygen) and a reverse reaction (decomposition of the oxyhemoglobin complex).
Upon inhalation of oxygen, it accesses the blood of a person and binds to hemoglobin, so the following reaction proceeds to the right.
Similarly, the opposite process takes place in muscles, oxyhemoglobin is decomposed back into hemoglobin and oxygen.
The equilibrium constant reaction is relatively high, since at standard conditions, this is a spontaneous reaction, hemoglobin combines with oxygen without any additional external source of energy.
The reaction of Hb with oxygen is an equilibrium reaction, with the right reaction proceeding in the lungs, and the left reaction proceeding in muscles.
What is the reaction of Hb with oxygen?
The reaction of Hb with oxygen determines the oxygen-carrying capacity of Hb. The Hb is the blood constituent that carries the oxygen from the lungs to different parts of the body.
The reaction in the forward direction is indicated with the right arrow, and the backward direction is indicated with the left arrow. The double arrow reaction indicates the presence of an equilibrium reaction ion in which the rate of forwarding and backward reaction is equal.
Thus, the reaction of Hb with oxygen to form Haemeoxyglobin is an equilibrium reaction.
The forward reaction is favored when the concentration of oxygen is higher to bind with the Hb molecules. Thus, the right reaction is favored with the inhalation of oxygen in the lungs.
In muscles, the concentration of oxygen is less, thereby the breakdown of the complex takes place, and the reaction proceeds in the left direction.
The K values determine the rate of formation of the product with respect to the reactant. The K value higher than 1 favor product formation, and less than 1 favors reactant formation.
Since the reaction is in equilibrium, the K value is 1.
Thus, the statements correct for the oxyhemoglobin formation reaction are A, B, and C.
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