Answer:
a) tp = 10 msec. b) = d/s c) No d) No
Explanation:
a) The propagation time for a packet of L bytes, over a link with a transmission rate of R bps, is given by the relationship between the distance traveled, and the propagation speed across the physical medium, assumed to be constant, as follows:
s = Δx/Δt ⇒ Δt = Δx/s
In our case, we know that Δx=d=2.5*10³ km = 2.5*10⁶ m, and that s= 2.5*10⁸ m/s, so replacing in (1), we get:
tp = Δt = 2.5*10⁶ m / 2.5*10⁸ m/s = 10⁻² sec. = 10 msec.
b) As stated above, the propagation time (not the total delay time that involves the transmission delay also) is given by a fixed relationship, as follows:
tp = Δx/v = d/s
c) As stated above, the propagation delay does not depend on packet length.
d) As stated above, the propagation delay does not depend on transmission rate.
