Respuesta :
For this case:
D.-) The system has infinitely many solutions.
Explanation:
Remember that you have to write complete questions in order to find exact and good answers. In this exercise, the system is missing. However, I'll provide the following system:
[tex]\text{\ensuremath{\left.\begin{array}{c}(1)\\(2)\end{array}\right.\left\{ \begin{array}{c}3x+y=-6\\6x+2y=-12\end{array}\right.}}[/tex]
So we have two equations and two variables. Our first equation is:
[tex]3x+y=-6[/tex]
And the second equation is:
[tex]6x+2y=-12[/tex]
When graphing these two lines, we can get the following possibilities:
- They have a unique solution. This means the graphs intersect at a single point.
- They have infinitely many solutions. This implies the lines are basically the same.
- They have no solution. This implies they are parallel but with different y-intersect.
By dividing equation (2) by 2 we get:
[tex]\frac{6x+2y}{2}=\frac{-12}{2} \\ \\ 3x+y=-6[/tex]
So we get the same equation as line (1), so the conclusion is that they have infinitely many solutions.
Learn more:
Infinitely many solutions: https://brainly.com/question/13771057
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