Answer:
The velocity of 50 kg skater is 0.67 m/s.
Explanation:
Given that,
Mass of one ice skater = 40 kg
Mass of other ice skater = 50 kg
Speed of first = 1.5 m/s
Let the velocity of 40 kg and 50 kg skater be v and V respectively.
We need to calculate the velocity of 50 kg skater
Using law of conservation of momentum
As they start from rest , their initial momentum is zero.
[tex]mv=m_{1}v_{1}+m_{2}v_{2}[/tex]
Put the value into the formula
[tex]0=40v+50V[/tex]
[tex]v=-\dfrac{5V}{4}[/tex]
Also relative velocity of separation is 1.5 m/s.
Using formula of relative velocity V'
[tex]V'=V-v[/tex]
[tex]1.5=V-v[/tex]
Put the value of v in to the formula
[tex]1.5=V+\dfrac{5V}{4}[/tex]
[tex]1.5=\dfrac{9V}{4}[/tex]
[tex]V=\dfrac{1.5\times4}{9}[/tex]
[tex]V=0.67\ m/s[/tex]
Hence, The velocity of 50 kg skater is 0.67 m/s.
