Respuesta :
Answer:
four less than the quotient of a number cubed and seven, increased by three [tex](\frac{n^3}{7} -4)+3[/tex]
five times the difference of a number squared and six
[tex]5(n^2 -6)[/tex]
nine more than the quotient of six and a number cubed, decreased by four
[tex]9+\frac{6}{n^3}-4[/tex]
twice the difference of nine and a number squared
[tex]2(9-n^2)[/tex]
Step-by-step explanation:
Let n the number of interest we have this:
four less than the quotient of a number cubed and seven, increased by three [tex](\frac{n^3}{7} -4)+3[/tex]
five times the difference of a number squared and six
[tex]5(n^2 -6)[/tex]
nine more than the quotient of six and a number cubed, decreased by four
[tex]9+\frac{6}{n^3}-4[/tex]
twice the difference of nine and a number squared:
[tex]2(9-n^2)[/tex]
Answer:
D-twice the difference of nine and a number squared; 2 (9 minus n squared)
Step-by-step explanation:
Got it right on test
