Respuesta :
Answer:
The volume at the surface is 10.97 L.
Explanation:
Given that,
Volume = 5.5 L
Height = 10 m
Density of sea water= 1025 kg/m³
We need to calculate the pressure at that point
Using formula of pressure
[tex]P'=P+\rho gh[/tex]
Put the value into the formula
[tex]P'=1.01\times10^{5}+1025\times9.8\times10[/tex]
[tex]P'=201450\ Pa[/tex]
We need to calculate the volume at the surface
Using equation of ideal gas
[tex]PV= RT[/tex]
So, for both condition
[tex]PV=P'V'[/tex]
Put the value into the formula
[tex]V=\dfrac{201450\times5.5}{1.01\times10^{5}}[/tex]
[tex]V=10.97\ L[/tex]
Hence, The volume at the surface is 10.97 L.
Answer:
10.95 L
Explanation:
Let the pressure at depth 10 m is P1.
V1 = 5.5 L
P1 = Po + h x d x g
P2 is the pressure at the surface
P2 = Po
where, Po be the atmospheric pressure = 1.01 x 10^5 Pa
Let V2 be the volume at the surface.
Use P1 x V1 = P2 x V2
(Po + 10 x 1025 x 9.8) x 5.5 = Po x V2
(1.01 x 10^5 + 1 x 10^5) x 5.5 = 1.01 x 10^5 x V2
2.01 x 5.5 = 1.01 x V2
V2 = 10.95 L
