Answer:
Work done, W = 19.6 J
Explanation:
It is given that,
Mass of the block, m = 5 kg
Speed of the block, v = 10 m/s
The coefficient of kinetic friction between the block and the rough section is 0.2
Distance covered by the block, d = 2 m
As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.
[tex]W=\mu_kmgd[/tex]
[tex]W=0.2\times 5\times 9.8\times 2[/tex]
W = 19.6 J
So, the change in the kinetic energy of the block as it passes through the rough section is 19.6 J. Hence, this is the required solution.
The change in the kinetic energy of the block as it passes through the rough section is 19.6 J.
Given data:
The mass of block is, m = 5 kg.
The speed of block is, v = 10 m/s.
Length of rough section is, d = 2 m.
The coefficient of kinetic friction between the block and the rough section is, [tex]\mu = 0.2[/tex].
As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.
So,
[tex]W = \mu \times mgd\\\\W = 0.2 \times 5 \times 9.8 \times 2\\\\W = 19.6 \;\rm J[/tex]
Thus, we can conclude that the change in the kinetic energy of the block as it passes through the rough section is 19.6 J.
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