Answer:
answer is almost 0 i.e impossible event.
Step-by-step explanation:
given that the the true population proportion were
p= 0.5
a) Std deviation of sample proportion = [tex]\sqrt{\frac{pq}{n} } \\=0.0707[/tex]
This is the std deviation for a single trial. We know in binomial variance is npq. Using this we can say for a single trial, variance would be pq/n and hence std deviation of proportion is square root of pq/n
b) The probability that the sample proportion will be larger than 0.55 for a random sample ofsize 50
= P(p>0.55)
= [tex]P(Z>\frac{0.05}{0.0707} )\\= P(Z>7.07)\\<0.00001[/tex]
