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A thick window pane 0.367 cm has an area of 1.247 square meters. The temperature difference between the inside and outside surfaces of the window is 33.2°C. What is the rate of heat flow through this window in J/s if the thermal conductivity for glass is 0.8 J/s/m/°C?A. 9.025B. 9025C. 902.5D. 90.25

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Answer:

B. 9025 J/s

Explanation:

thickness (d) = 0.367 cm = 0.00367 m

area (A) = 1.247 m^{2}

temperature difference (ΔT) =33.2 °C

thermal conductivity (K) = 0.8 J/s/m/°C

find the rate of heat flow

rate of heat flow = [tex]\frac{K.A.ΔT}{d}[/tex]

rate of heat flow = [tex]\frac{0.8x1.247x33.2}{0.00367}[/tex]

rate of heat flow = 9024.6 ≈ 9025 J/s

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