Answer:
25.907°C
Explanation:
In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C
The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.
Thus:
[tex]-q_{combust} = q_{water} + q_{calori}[/tex]
[tex]q_{combust}[/tex] = heat of combustion of benzoic acid
[tex]q_{water}[/tex] = heat energy released to water
[tex]q_{calori}[/tex] = heat energy released to the calorimeter
Therefore,
[tex]-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})[/tex]
1.056*26.42 = [0.987*4.18 + 6.66]([tex]T_{f}[/tex] - 23.32)
27.8995 = [4.12566+6.660]([tex]T_{f}[/tex] - 23.32)
([tex]T_{f}[/tex] - 23.32) = 27.8995/10.7857 = 2.587
[tex]T_{f}[/tex] = 23.32 + 2.587 = 25.907°C
