Answer:
0.033 is the probability that a teenage boy has a cholesterol level greater than 225.
Step-by-step explanation:
The following information is missing in the question:
Mean, μ = 170
Standard Deviation, σ = 30
Using the given information, we may solve the question as:
We are given that the distribution of distribution of cholesterol levels in teenage boys is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
a) P( cholesterol level greater than 225)
P(x > 225)
[tex]P( x > 225) = P( z > \displaystyle\frac{225 - 170}{30}) = P(z > 1.833)[/tex]
[tex]= 1 - P(z \leq 1.833)[/tex]
Calculation the value from standard normal z table, we have,
[tex]P(x > 225) = 1 - 0.967= 0.033 = 3.3\%[/tex]
0.033 is the probability that a teenage boy has a cholesterol level greater than 225.
