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A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson’s ratio of 0.35 is pulled in tension with force of 40,000 N. If the deformation is totally elastic, what is the strain experienced by the specimen?

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opudodennis

Answer:

0.00116

Explanation:

Tensile modulus, [tex]E=\frac {Stress}{Strain}[/tex]

Making strain the subject then

[tex]Strain=\frac {Stress}{E}[/tex]

Since [tex]stress=\frac {F}{A}[/tex] then

[tex]Strain=\frac {F}{AE}=\frac {40000}{\pi 0.01^{2}\times 110\times 10^{9}}=0.00115749\approx 0.00116[/tex]

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