Respuesta :
Answer:
Explanation:
Given
Depth of Water is same for Both glasses
Glass 1 has diameter twice of diameter of Glass 2
Pressure at the Bottom is given by
[tex]P=\rho gh[/tex]
where [tex]\rho =density\ of\ water[/tex]
[tex]g=acceleration\ due\ to\ gravity[/tex]
[tex]h=depth\ of\ bottom\ Surface\ from\ free\ surface\ of\ Fluid[/tex]
Since depth is same for both glass therefore Pressure at bottom is same
[tex]Weight=mass\times g[/tex]
[tex]Weight=\rho \times V\times g[/tex]
[tex]Weight=\rho \times A\times h\times g[/tex]
[tex]Weight=\rho \times \frac{\pi d^2}{4}\times h\times g[/tex]
since weight is proportional to [tex]d^2[/tex] therefore weight of First glass will be more
