Demographic experts say that the population, P, of China, in billions, can be approximated by the function P = 1.15(1.014)^+where t is the number of years since the start of 1993. Using this model, estimate how much faster the Chinese population will be growing in 2016 than in 2003. (Be sure to use enough decimal places (6 or more) in your calculations.) a) 3.64 million people / year b) 5.46 million people / year c) 5.1 million people / year

Respuesta :

Answer:

a) 3.64 million people / year

Step-by-step explanation:

The population of China, in billions, is represented by the following function:

[tex]P(t) = 1.15*(1.014)^{t}[/tex]

The growth rate of the population after the year t after 1993 is given by [tex]P'(t)[/tex]

So

[tex]P'(t) = 1.15*(1.014)^{t}*\ln{1.014}[/tex]

[tex]P'(t) = 0.016*(1.014)^{t}[/tex]

2003

2003 is 10 years after 1993. So

[tex]P'(10) = 0.016*(1.014)^{10} = 0.018387[/tex]

The growth rate is 2003 is 0.018387 billion people a year.

2016

2016 is 23 years after 1993. So:

[tex]P'(23) = 0.016*(1.014)^{23} = 0.022029[/tex]

The growth rate is 2016 is 0.022029 billion people a year.

0.022029 - 0.018387 = 0.003642 = 3.642 million faster a year in 2016 than in 2003.

The correct answer is:

a) 3.64 million people / year

znk

Answer:

a) 3.64 million people per year  

Step-by-step explanation:

  Let y = the year.

Then t = y - 1993

The rate of change of the function is the derivative with respect to t.

[tex]\dfrac{\text{d}{P}}{\text{d}t} = \dfrac{\text{d[1.15(1.014)}^{t}]}{\text{d}t} = 1.15(1.014)^{t}\ln (1.014) =P \ln(1.014)[/tex]

Let's make a table to keep the calculations straight

[tex]\begin{array}{ccccc}\textbf{Year} & \mathbf{t} & \mathbf{(1.014)}^{\mathbf{t}} & \mathbf{P} & \mathbf{\textbf{d}P/{\text{d}}t}\\2003 & 10& 1.149 157 &1.321 531& 0.018 373\\2016 & 23& 1.376 806& 1.583 327&0.022 013 \\\end{array}\\[/tex]

(0.022 012 855 - 0.018 373 122) billion = 0.003 64 billion = 3.64 million

So, the Chinese population in 2016 was growing by 3.64 million people per year faster than in 2003.