A woman pushes a lawn mower with a constant force of 112 Newtons at an angle of 37◦ with respect to the horizontal. The lawn mower moves at a speed of 20 cm/sec. What is her power output? (1 hp = 746 Watts)

1. 0.024 hp
2. 0.030 hp
3. 0.020 hp
4. 0.040 hp
5. 0.044 hp
6. 0.034 hp

Respuesta :

Answer:

1.0.024 hp

Step-by-step explanation:

We are given that

Constant force=F=112 N

[tex]\theta=37^{\circ}[/tex]

Speed of lawn mower,v=20 cm/s=[tex]20\times 10^{-2} m/s[/tex]

1 m=100 cm

1 hp=746 watt

We have to find the power output

Force applied by women on lawn mower=[tex]Fcos\theta=112cos 37^{\circ}[/tex]

Force applied by women on lawn mower=[tex]89.45[/tex]N

Power output,P=[tex]Fv[/tex]

Using the formula

Power output=[tex]89.45\times 20\times 10^{-2}=17.89 watt[/tex]

Power output,P=[tex]\frac{17.89}{746}=0.024[/tex]hp

Hence, option 1 is true